Practice Problem
LRU Cache
Difficulty: Medium
Design a data structure that follows the Least Recently Used (LRU) cache constraints, supporting get and put operations in O(1) time.
LRU Cache
Design a data structure that follows the constraints of a Least Recently Used (LRU) cache.
Implement the LRUCache class:
LRUCache(capacity): Initialize the LRU cache with a positive sizecapacity.get(key): Return the value of thekeyif the key exists, otherwise return-1.put(key, value): Update the value of thekeyif the key exists. Otherwise, add the key-value pair to the cache. If the number of keys exceeds thecapacity, evict the least recently used key.
Both get and put must run in O(1) average time complexity.
Examples
Example 1:
Input:
["LRUCache", "put", "put", "get", "put", "get", "put", "get", "get", "get"]
[[2], [1, 1], [2, 2], [1], [3, 3], [2], [4, 4], [1], [3], [4]]
Output:
[null, null, null, 1, null, -1, null, -1, 3, 4]
Explanation:
LRUCache cache = new LRUCache(2);
cache.put(1, 1); // cache is {1=1}
cache.put(2, 2); // cache is {1=1, 2=2}
cache.get(1); // return 1
cache.put(3, 3); // evicts key 2, cache is {1=1, 3=3}
cache.get(2); // return -1 (not found)
cache.put(4, 4); // evicts key 1, cache is {4=4, 3=3}
cache.get(1); // return -1 (not found)
cache.get(3); // return 3
cache.get(4); // return 4Constraints
1 <= capacity <= 30000 <= key <= 10^40 <= value <= 10^5- At most
2 * 10^5calls will be made togetandput.
Expected Complexity
- Time: O(1) for both
getandput - Space: O(capacity)
MEDIUM
Singly Linked List
Doubly Linked List
Hash Map / Dictionary
LRU Cache
Intermediate
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